Let us consider the following frequency distribution table which gives the weights of $38$ students of a class:

Weights (in $kg$)	Number of students
$31-35$	$9$
$36-40$	$5$
$41-45$	$14$
$46-50$	$3$
$51-55$	$1$
$56-60$	$2$
$61-65$	$2$
$66-70$	$1$
$71-75$	$1$
Total	$38$

If two new students of weights $35.5\, kg$ and $40.5\, kg$ are admitted to this class,how should the frequency distribution table be adjusted to include them?

(N/A) To include weights like $35.5\, kg$ and $40.5\, kg$,we must convert the discontinuous class intervals into continuous ones.
$1$. Calculate the difference between the upper limit of a class and the lower limit of the next class (e.g.,$36 - 35 = 1$).
$2$. Divide this difference by $2$ to get the adjustment factor $(1 / 2 = 0.5)$.
$3$. Subtract $0.5$ from each lower limit and add $0.5$ to each upper limit to make the classes continuous.
The new continuous intervals are: $30.5-35.5, 35.5-40.5, 40.5-45.5, 45.5-50.5, 50.5-55.5, 55.5-60.5, 60.5-65.5, 65.5-70.5, 70.5-75.5$.
By convention,the upper limit value is included in the next class interval. Therefore,$35.5$ is included in $35.5-40.5$ and $40.5$ is included in $40.5-45.5$.
The updated table is:

Weights (in $kg$)	Number of students
$30.5-35.5$	$9$
$35.5-40.5$	$6$
$40.5-45.5$	$15$
$45.5-50.5$	$3$
$50.5-55.5$	$1$
$55.5-60.5$	$2$
$60.5-65.5$	$2$
$65.5-70.5$	$1$
$70.5-75.5$	$1$
Total	$40$