In a pure silicon $(n_i = 10^{16}/m^3)$ crystal at $300\, K$,$10^{21}$ atoms of phosphorus are added per cubic meter. The new hole concentration will be

  • A
    $10^{21}\, m^{-3}$
  • B
    $10^{19}\, m^{-3}$
  • C
    $10^{11}\, m^{-3}$
  • D
    $10^5\, m^{-3}$

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What is the conductivity of a pure silicon crystal at $300 \ K$? The number of electron-hole pairs per $cm^3$ is $1.072 \times 10^{10}$. Given $\mu_n = 1350 \ cm^2/V \cdot s$ and $\mu_p = 480 \ cm^2/V \cdot s$.

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The concentration of electrons in an intrinsic semiconductor is $6 \times 10^{15} \,m^{-3}$. On doping with an impurity, the electron concentration increases to $4 \times 10^{22} \,m^{-3}$. In thermal equilibrium, the concentration of the holes in the doped semiconductor is:

In a semiconductor,the ratio of the number of electrons to the number of holes is $7/5$ and the ratio of their currents is $7/4$. What is the ratio of their drift velocities?

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