In a region,the intensity of an electric fiel | vedclass

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(A) The electric flux $\phi$ through a surface is defined as the dot product of the electric field vector $\overrightarrow{E}$ and the area vector $\o

Vedclass · Accepted Answer

$20 	ext{ Nm}^2 	ext{C}^{-1}$

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(A) The electric flux $\phi$ through a surface is defined as the dot product of the electric field vector $\overrightarrow{E}$ and the area vector $\overrightarrow{A}$.Given:$\overrightarrow{E} = (2 \hat{i} + 3 \hat{j} + \hat{k}) 	ext{ NC}^{-1}$$\overrightarrow{A} = 10 \hat{i} 	ext{ m}^2$Using the formula $\phi = \overrightarrow{E} \cdot \overrightarrow{A}$:$\phi = (2 \hat{i} + 3 \hat{j} + \hat{k}) \cdot (10 \hat{i})$Since $\hat{i} \cdot \hat{i} = 1$,$\hat{i} \cdot \hat{j} = 0$,and $\hat{i} \cdot \hat{k} = 0$:$\phi = (2 	imes 10) 	ext{ Nm}^2 	ext{C}^{-1} = 20 	ext{ Nm}^2 	ext{C}^{-1}$.

In a region,the intensity of an electric field is given by $\overrightarrow{E}=(2 \hat{i}+3 \hat{j}+\hat{k}) \text{ NC}^{-1}$. The electric flux through a surface of area $10 \hat{i} \text{ m}^2$ in the region is

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