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(B) The reverse bias resistance $(R)$ of a diode is defined as the ratio of the change in voltage $(\Delta V)$ to the change in current $(\Delta I)$.G

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$2 	imes 10^{6} \, \Omega$

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(B) The reverse bias resistance $(R)$ of a diode is defined as the ratio of the change in voltage $(\Delta V)$ to the change in current $(\Delta I)$.Given:Change in voltage, $\Delta V = 1 \, V$Change in current, $\Delta I = 0.5 \, \mu A = 0.5 	imes 10^{-6} \, A$Using the formula:$R = \frac{\Delta V}{\Delta I}$$R = \frac{1}{0.5 	imes 10^{-6}} \, \Omega$$R = \frac{1}{0.5} 	imes 10^{6} \, \Omega$$R = 2 	imes 10^{6} \, \Omega$Therefore, the reverse bias resistance is $2 	imes 10^{6} \, \Omega$.

Condition	$V$	$I$
Forward biasing	$2.0 \, V$	$60 \, mA$
Forward biasing	$2.4 \, V$	$80 \, mA$
Reverse biasing	$0 \, V$	$0 \, \mu A$
Reverse biasing	$-2 \, V$	$-0.25 \, \mu A$

In a reverse biased diode, when the applied voltage changes by $1 \, V$, the current is found to change by $0.5 \, \mu A$. The reverse bias resistance of the diode is

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