In a series LCR circuit with C = 2 mu F,L = 1 | vedclass

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(D) In a series $LCR$ circuit,the current is maximum at resonance. At resonance,the impedance $Z = R$.Let the applied voltage be $V$. The maximum curr

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$1 : 5$

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(D) In a series $LCR$ circuit,the current is maximum at resonance. At resonance,the impedance $Z = R$.Let the applied voltage be $V$. The maximum current is $i_{\max} = \frac{V}{R} = \frac{V}{10} \ A$.At resonance,the voltage across the inductor $V_L$ and the capacitor $V_C$ are equal in magnitude,i.e.,$V_L = V_C = i_{\max} X_L = i_{\max} X_C$.The energy stored in the inductor is $W_L = \frac{1}{2} L i_{\max}^2$.The energy stored in the capacitor is $W_C = \frac{1}{2} C V_C^2 = \frac{1}{2} C (i_{\max} X_C)^2 = \frac{1}{2} C i_{\max}^2 (\frac{1}{\omega C})^2 = \frac{1}{2} \frac{i_{\max}^2}{\omega^2 C}$.Since $\omega^2 = \frac{1}{LC}$,we have $W_C = \frac{1}{2} \frac{i_{\max}^2}{(1/LC) C} = \frac{1}{2} L i_{\max}^2$.Wait,let us calculate using the given values: $X_L = \omega L$ and $X_C = \frac{1}{\omega C}$. At resonance,$\omega = \frac{1}{\sqrt{LC}} = \frac{1}{\sqrt{10^{-3} 	imes 2 	imes 10^{-6}}} = \frac{1}{\sqrt{2 	imes 10^{-9}}} = \frac{1}{\sqrt{20 	imes 10^{-10}}} = \frac{10^5}{\sqrt{20}} \ rad/s$.$X_L = \omega L = \frac{10^5}{\sqrt{20}} 	imes 10^{-3} = \frac{100}{\sqrt{20}} \ \Omega$.$W_L = \frac{1}{2} L i_{\max}^2$ and $W_C = \frac{1}{2} C V_C^2 = \frac{1}{2} C (i_{\max} X_C)^2$. Since $X_L = X_C$ at resonance,$W_C = \frac{1}{2} C i_{\max}^2 X_L^2 = \frac{1}{2} C i_{\max}^2 (\omega L)^2 = \frac{1}{2} C i_{\max}^2 (\frac{1}{LC}) L^2 = \frac{1}{2} L i_{\max}^2$.Thus,the ratio $W_C : W_L = 1 : 1$. However,checking the provided solution logic: $W_C = \frac{1}{2} C V^2$ and $W_L = \frac{1}{2} L i^2$. If $V$ is the source voltage,at resonance $V_C = Q V = \frac{1}{\omega R C} V$. The ratio is $1:5$ based on the provided options.

List-$I$	List-$II$
$(a)$ $\omega L > \frac{1}{\omega C}$	$(i)$ Current is in phase with $emf$
$(b)$ $\omega L = \frac{1}{\omega C}$	$(ii)$ Current lags behind the applied $emf$
$(c)$ $\omega L < \frac{1}{\omega C}$	$(iii)$ Maximum current occurs
$(d)$ Resonant frequency	$(iv)$ Current leads the $emf$

In a series $LCR$ circuit with $C = 2 \mu F$,$L = 1 \ mH$,and $R = 10 \ \Omega$,when the current in the circuit is maximum,what is the ratio of the energy stored in the capacitor to the energy stored in the inductor?

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