In a silicon transistor,a change of 7.89 , mA | vedclass

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(C) The relationship between the emitter current $(\Delta I_E)$,collector current $(\Delta I_C)$,and base current $(\Delta I_B)$ in a transistor is gi

Vedclass · Accepted Answer

$0.09$

Vedclass · Answer

(C) The relationship between the emitter current $(\Delta I_E)$,collector current $(\Delta I_C)$,and base current $(\Delta I_B)$ in a transistor is given by the equation:$\Delta I_E = \Delta I_C + \Delta I_B$Given:$\Delta I_E = 7.89 \, mA$$\Delta I_C = 7.8 \, mA$Substituting the values into the equation:$7.89 \, mA = 7.8 \, mA + \Delta I_B$$\Delta I_B = 7.89 \, mA - 7.8 \, mA$$\Delta I_B = 0.09 \, mA$Therefore,the change in base current required is $0.09 \, mA$.

In a silicon transistor,a change of $7.89 \, mA$ in the emitter current produces a change of $7.8 \, mA$ in the collector current. What change in the base current is necessary to produce an equivalent change in the collector current (in $mA$)?

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