In a triangle $ABC$,$\angle BAC = 90^{\circ}$; $AD$ is the altitude from $A$ onto $BC$. Draw $DE$ perpendicular to $AC$ and $DF$ perpendicular to $AB$. Suppose $AB = 15$ and $BC = 25$. Then the length of $EF$ is

  • A
    $12$
  • B
    $10$
  • C
    $5 \sqrt{3}$
  • D
    $5 \sqrt{5}$

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