In finding the electric field using Gauss's Law,the formula $|\overrightarrow{E}| = \frac{q_{enc}}{\varepsilon_{0}|A|}$ is applicable. In the formula,$\varepsilon_{0}$ is the permittivity of free space,$A$ is the area of the Gaussian surface,and $q_{enc}$ is the charge enclosed by the Gaussian surface. The equation can be used in which of the following situations?
- AOnly when the Gaussian surface is an equipotential surface.
- BOnly when $|\overrightarrow{E}|$ is constant on the surface.
- CFor any choice of Gaussian surface.
- DOnly when the Gaussian surface is an equipotential surface and $|\overrightarrow{E}|$ is constant on the surface.
Explore More
Similar Questions
An infinitely long positively charged straight thread has a linear charge density $\lambda \text{ Cm}^{-1}$. An electron revolves along a circular path having its axis along the length of the wire. The graph that correctly represents the variation of the kinetic energy of the electron as a function of the radius $r$ of the circular path from the wire is:
DifficultJEE MAIN 2024
View SolutionMatch List-$I$ with List-$II$:
List-$I$ List-$II$ $(A)$ Electric field inside (distance $r < R$ from center) of a uniformly charged spherical shell with surface charge density $\sigma$ and radius $R$. $(I)$ $\sigma / \varepsilon_0$ $(B)$ Electric field at distance $r$ from a uniformly charged infinite plane sheet with surface charge density $\sigma$. $(II)$ $\sigma / 2 \varepsilon_0$ $(C)$ Electric field outside (distance $r > R$ from center) of a uniformly charged spherical shell with surface charge density $\sigma$ and radius $R$. $(III)$ $0$ $(D)$ Electric field between $2$ oppositely charged infinite plane parallel sheets with uniform surface charge density $\sigma$. $(IV)$ $\frac{\sigma R^2}{\varepsilon_0 r^2}$
Choose the correct answer from the options given below:
| List-$I$ | List-$II$ |
| $(A)$ Electric field inside (distance $r < R$ from center) of a uniformly charged spherical shell with surface charge density $\sigma$ and radius $R$. | $(I)$ $\sigma / \varepsilon_0$ |
| $(B)$ Electric field at distance $r$ from a uniformly charged infinite plane sheet with surface charge density $\sigma$. | $(II)$ $\sigma / 2 \varepsilon_0$ |
| $(C)$ Electric field outside (distance $r > R$ from center) of a uniformly charged spherical shell with surface charge density $\sigma$ and radius $R$. | $(III)$ $0$ |
| $(D)$ Electric field between $2$ oppositely charged infinite plane parallel sheets with uniform surface charge density $\sigma$. | $(IV)$ $\frac{\sigma R^2}{\varepsilon_0 r^2}$ |
Choose the correct answer from the options given below:
$A$ thin metallic spherical shell of radius $r$ contains a charge $Q$ on its surface. $A$ point charge $q_1$ is placed at the centre of the shell and another charge $q_2$ is placed outside the shell at a distance $x$ from the centre. Then, the forces on charges $q_1$ and $q_2$ respectively are
Charges $Q, 2Q$ and $4Q$ are uniformly distributed in three dielectric solid spheres $1, 2$ and $3$ of radii $R/2, R$ and $2R$ respectively,as shown in the figure. If magnitudes of the electric fields at point $P$ at a distance $R$ from the centre of spheres $1, 2$ and $3$ are $E_1, E_2$ and $E_3$ respectively,then:
DifficultIIT 2014
View SolutionTwo parallel large thin metal sheets have equal surface charge densities $\sigma = 26.4 \times 10^{-12} \ C/m^2$ of the same sign. The electric field between these sheets is:
MediumAIIMS 2019
View SolutionVedclass Products
For Students
Vedclass Test Series
Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.
Start Free TrialFor Teachers
Exam Paper Generator
Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.
Try FreeFor Institutes
Online Exam Module
Live online exams with unlimited students, 360° analytics & white-label branding.
See Demo