In the following two plots,psi^2 is plotted a | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) The number of radial nodes in an orbital is given by the formula $(n - l - 1)$.For the $1s$ orbital,$n=1$ and $l=0$,so the number of radial nodes

Vedclass · Accepted Answer

$'a'$ is for $1s$ and $'b'$ for $2s$

Vedclass · Answer

(A) The number of radial nodes in an orbital is given by the formula $(n - l - 1)$.For the $1s$ orbital,$n=1$ and $l=0$,so the number of radial nodes is $(1 - 0 - 1) = 0$.For the $2s$ orbital,$n=2$ and $l=0$,so the number of radial nodes is $(2 - 0 - 1) = 1$.Plot $(a)$ shows no nodes,which corresponds to the $1s$ orbital.Plot $(b)$ shows one radial node,which corresponds to the $2s$ orbital.Therefore,$'a'$ is for $1s$ and $'b'$ is for $2s$.

List-$I$ (Quantum Number)	List-$II$ (Information provided)
$A$. $m_l$	$I$. Shape of orbital
$B$. $m_s$	$II$. Size of orbital
$C$. $l$	$III$. Orientation of orbital
$D$. $n$	$IV$. Orientation of spin of electron

In the following two plots,$\psi^2$ is plotted against the distance '$r$' from the nucleus. Select the correct statement.

Similar Questions

Which of the following is the correct electronic configuration of $Cr$?

How many nodal planes are present in a $d$-orbital?

For a given azimuthal quantum number $(l)$,the total number of magnetic quantum numbers $(m)$ is given by:

What is the atomic number of the element with $M^{2+}$ ion having electronic configuration $[Ar] 3d^8$?

Vedclass Test Series

Exam Paper Generator

Online Exam Module