In a $1 \ m$ long open pipe,what is the harmonic of resonance obtained with a tuning fork of frequency $480 \ Hz$? (Assume the speed of sound $v = 330 \ m/s$)

For air at room temperature, the atmospheric pressure is $1.0 \times 10^{5} \text{ Nm}^{-2}$ and the density of air is $1.2 \text{ kgm}^{-3}$. For a tube of length $1.0 \text{ m}$, closed at one end, the lowest frequency generated is $84 \text{ Hz}$. The value of $\gamma$ (ratio of two specific heats) for air is:

$A$ closed organ pipe of length $1.2 \, m$ vibrates in its first overtone mode. The pressure variation is maximum at:

Give the equation for the normal modes of vibration for a closed pipe.

$A$ closed organ pipe and an open organ pipe have their first overtones identical in frequency. Their lengths are in the ratio:

If $l_1$ and $l_2$ are the lengths of the air column for the first and second resonance when a tuning fork of frequency $n$ is sounded on a resonance tube,then the distance of the displacement antinode from the top end of the resonance tube is: