In quadratic equation ax^{2} + bx + c = 0,whe | vedclass

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(C) The quadratic equation is given by $ax^{2} + bx + c = 0$.Given that $b = 0$,the equation simplifies to $ax^{2} + c = 0$.This implies $ax^{2} = -c$

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opposite

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(C) The quadratic equation is given by $ax^{2} + bx + c = 0$.Given that $b = 0$,the equation simplifies to $ax^{2} + c = 0$.This implies $ax^{2} = -c$,or $x^{2} = -c/a$.Taking the square root of both sides,we get $x = \pm \sqrt{-c/a}$.Let the roots be $\alpha$ and $\beta$. Then $\alpha = \sqrt{-c/a}$ and $\beta = -\sqrt{-c/a}$.Since $\alpha = -\beta$,the roots are equal in magnitude but opposite in sign.Therefore,the roots are opposite.

In quadratic equation $ax^{2} + bx + c = 0$,where $a \neq 0$,$b = 0$,and $D > 0$,then both the roots of the equation are .....

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