In quadrilateral PQRS,PQ = PS and RQ = RS. Pr | vedclass

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(N/A) $1$. Consider the two triangles $	riangle PQR$ and $	riangle PSR$.$2$. In these triangles,we are given that $PQ = PS$ (Side).$3$. We are also

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(N/A) $1$. Consider the two triangles $	riangle PQR$ and $	riangle PSR$.$2$. In these triangles,we are given that $PQ = PS$ (Side).$3$. We are also given that $RQ = RS$ (Side).$4$. The side $PR$ is common to both triangles,so $PR = PR$ (Side).$5$. By the $SSS$ (Side-Side-Side) congruence criterion,$	riangle PQR \cong 	riangle PSR$.$6$. Since the triangles are congruent,their corresponding parts are equal ($CPCT$ - Corresponding Parts of Congruent Triangles).$7$. Therefore,$\angle PQR = \angle PSR$.

In quadrilateral $PQRS$,$PQ = PS$ and $RQ = RS$. Prove that $\angle PQR = \angle PSR$.

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