In the circuit shown in the figure,the switch | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) Just after the switch $S$ is closed,the capacitors act as short circuits (wires) because they are initially uncharged. However,looking at the circ

Vedclass · Accepted Answer

Long time after the switch $S$ is closed,$I_1 = 0.6\,A, I_2 = 0$ and $I_3 = 0$.

Vedclass · Answer

(C) Just after the switch $S$ is closed,the capacitors act as short circuits (wires) because they are initially uncharged. However,looking at the circuit,the capacitors are in series with the $4\,\Omega$ resistor and in parallel with the $8\,\Omega$ resistor. At $t=0$,the capacitor acts as a wire,so the $4\,\Omega$ branch is effectively shorted. The circuit simplifies to the $6\,V$ battery in series with the $2\,\Omega$ resistor and the $8\,\Omega$ resistor. Thus,$I_1 = I_3 = 6\,V / (2\,\Omega + 8\,\Omega) = 0.6\,A$ and $I_2 = 0$.Long time after the switch $S$ is closed,the capacitors are fully charged and act as open circuits. The branch containing the $4\,\Omega$ resistor and the capacitor will have no current $(I_2 = 0)$. The circuit simplifies to the $6\,V$ battery in series with the $2\,\Omega$ and $8\,\Omega$ resistors. Thus,$I_1 = I_3 = 6\,V / (10\,\Omega) = 0.6\,A$ and $I_2 = 0$.

In the circuit shown in the figure,the switch $S$ is initially open and the capacitor is initially uncharged. $I_1, I_2$ and $I_3$ represent the current in the resistance $2\,\Omega, 8\,\Omega$ and $4\,\Omega$ respectively.

Similar Questions

An $RC$ circuit as shown in the figure is driven by an $AC$ source generating a square wave. The output wave pattern monitored by $CRO$ would look close to

Find the charge in steady state of the capacitor. (in $nC$)

$A$ capacitor of capacitance $C$ is connected in series with a resistance $R$ and a $DC$ source of $emf$ $E$ through a key. The capacitor starts charging when the key is closed. By the time the capacitor has been fully charged, what amount of energy is dissipated in the resistance $R$?

$A$ capacitor of capacity $0.1 \mu F$ connected in series to a resistor of $10 M \Omega$ is charged to a certain potential and then made to discharge through the resistor. The time in which the potential will take to fall to half its original value is (Given, $\log _{10} 2=0.3010$ ) (in $\,s$)

Assertion : $A$ capacitor blocks direct current in the steady state.
Reason : The capacitive reactance of the capacitor is inversely proportional to frequency $f$ of the source of $emf$.

Vedclass Test Series

Exam Paper Generator

Online Exam Module