In the given L-C circuit,inductance is 80 mu | vedclass

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(B) In an $L-C$ circuit,the total energy is conserved and oscillates between the magnetic field of the inductor and the electric field of the capacito

Vedclass · Accepted Answer

$40$

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(B) In an $L-C$ circuit,the total energy is conserved and oscillates between the magnetic field of the inductor and the electric field of the capacitor.The maximum energy stored in the capacitor is $U_{max} = \frac{1}{2} C V_{max}^2$.The maximum energy stored in the inductor is $U_{max} = \frac{1}{2} L I_{max}^2$.Equating these two,we get $\frac{1}{2} C V_{max}^2 = \frac{1}{2} L I_{max}^2$.Therefore,$I_{max} = V_{max} \sqrt{\frac{C}{L}}$.Given: $C = 20 \mu F = 20 	imes 10^{-6} \ F$,$L = 80 \mu H = 80 	imes 10^{-6} \ H$,and $V_{max} = 80 \ V$.Substituting the values: $I_{max} = 80 	imes \sqrt{\frac{20 	imes 10^{-6}}{80 	imes 10^{-6}}} = 80 	imes \sqrt{\frac{1}{4}} = 80 	imes \frac{1}{2} = 40 \ A$.

In the given $L-C$ circuit,inductance is $80 \mu H$ and capacitance is $20 \mu F$. The maximum potential difference across the capacitor is $80 \ V$. The maximum current is (in $A$)

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