In the given reactionCH_3CH_2CH=CHCH_3 xright | vedclass

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(D) The reaction represents the oxidative cleavage of an alkene using a strong oxidizing agent.$CH_3CH_2CH=CHCH_3$ undergoes oxidative cleavage with a

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$KMnO_4/OH^{-}$

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(D) The reaction represents the oxidative cleavage of an alkene using a strong oxidizing agent.$CH_3CH_2CH=CHCH_3$ undergoes oxidative cleavage with alkaline $KMnO_4$ followed by acidic workup.The double bond breaks to form carboxylic acids from the corresponding fragments.$CH_3CH_2CH=CHCH_3 \xrightarrow[(i) \ KMnO_4, OH^{-} 	ext{ (heat)}]{(ii) \ H^{+}} CH_3CH_2COOH + CH_3COOH$.Therefore,$X$ is $KMnO_4/OH^{-}$.

In the given reaction
$CH_3CH_2CH=CHCH_3$ $\xrightarrow{X}$ $CH_3CH_2COOH + CH_3COOH$
The $X$ is

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In the given reaction$CH_3CH_2CH=CHCH_3$ $\xrightarrow{X}$ $CH_3CH_2COOH + CH_3COOH$The $X$ is