In the reaction shown,the electrophile involv | vedclass

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(D) The given reaction is the Reimer-Tiemann reaction,where phenol reacts with chloroform $(CHCl_3)$ in the presence of aqueous sodium hydroxide $(NaO

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dichlorocarbene $(:CCl_2)$

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(D) The given reaction is the Reimer-Tiemann reaction,where phenol reacts with chloroform $(CHCl_3)$ in the presence of aqueous sodium hydroxide $(NaOH)$ to form salicylaldehyde.In this reaction,the electrophile is generated from chloroform.First,$CHCl_3$ reacts with $OH^-$ to form the trichloromethyl anion $(\stackrel{\ominus}{C}Cl_3)$.This anion then undergoes $\alpha$-elimination by losing a chloride ion $(Cl^-)$ to form dichlorocarbene $(:CCl_2)$.Dichlorocarbene is an electron-deficient species with a sextet of electrons,making it a strong electrophile.

In the reaction shown,the electrophile involved is:

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