Intermediates formed in the reactions P and Q | vedclass

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(B) The peroxide effect (Kharasch effect) is only observed with $HBr$ and not with $HCl$ or $HI$.In reaction $P$,the electrophilic addition of $HCl$ t

Vedclass · Accepted Answer

$P 	o CH_3-CH^{+}CH_3$,$Q 	o CH_3-CH^{+}CH_3$

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(B) The peroxide effect (Kharasch effect) is only observed with $HBr$ and not with $HCl$ or $HI$.In reaction $P$,the electrophilic addition of $HCl$ to propene follows Markovnikov's rule,forming the stable secondary carbocation intermediate $CH_3-CH^{+}CH_3$.In reaction $Q$,despite the presence of peroxide,$HCl$ does not undergo free-radical addition because the bond dissociation energy of $H-Cl$ is too high for the peroxide to initiate the radical chain mechanism.Therefore,reaction $Q$ also proceeds via the electrophilic addition mechanism,forming the same secondary carbocation intermediate $CH_3-CH^{+}CH_3$.

Intermediates formed in the reactions $P$ and $Q$ are:
$P: CH_3-CH=CH_2 \xrightarrow{HCl}$
$Q: CH_3-CH=CH_2 \xrightarrow[\text{Peroxide}]{HCl}$

Similar Questions

Stability order of the following carbocations is:
$(i)$ $CH_3-C^{+}(CH_3)-CH_2-CH_3$
$(ii)$ $CH_3-CH^{+}-CH_3$
$(iii)$ $CH_3-C^{+}(CH_3)-CH_3$
$(iv)$ $Ph-CH^{+}-CH_3$

The correct order of stability of the given carbanions is:

Arrange the following anions in decreasing order of their stability:
$CH_3^{\Theta}, NH_2^{\Theta}, OH^{\Theta}, Cl^{\Theta}$

Among the following, which is the most stable carbocation?

Determine the decreasing order of stability for the following carbocations: $(I) \ CH_3-C^+(CH_3)-CH_3$,$(II) \ CH_3-CH^+(OCH_3)$,$(III) \ CH_3-CH^+(COCH_3)$.

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Intermediates formed in the reactions $P$ and $Q$ are:$P: CH_3-CH=CH_2 \xrightarrow{HCl}$$Q: CH_3-CH=CH_2 \xrightarrow[\text{Peroxide}]{HCl}$