Let $f : (4, 6) \to (6, 8)$ be a function defined by $f(x) = x + [\frac{x}{2}]$ (where $[.]$ denotes the greatest integer function),then $f^{-1}(x)$ is equal to
- A$x - [\frac{x}{2}]$
- B$-x - 2$
- C$x - 2$
- D$\frac{1}{x + [\frac{x}{2}]}$
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