Let A = {1, 2, 3}. The total number of distin | vedclass

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(A) relation over a set $A$ is defined as any subset of the Cartesian product $A 	imes A$.Given $A = \{1, 2, 3\}$,the number of elements in $A$ is $n

Vedclass · Accepted Answer

$2^9$

Vedclass · Answer

(A) relation over a set $A$ is defined as any subset of the Cartesian product $A 	imes A$.Given $A = \{1, 2, 3\}$,the number of elements in $A$ is $n(A) = 3$.The number of elements in the Cartesian product $A 	imes A$ is $n(A 	imes A) = n(A) 	imes n(A) = 3 	imes 3 = 9$.The total number of subsets of a set with $m$ elements is $2^m$.Therefore,the total number of distinct relations that can be defined over $A$ is the number of subsets of $A 	imes A$,which is $2^9$.

Let $A = \{1, 2, 3\}$. The total number of distinct relations that can be defined over $A$ is

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