Let $S_{n}$ be the sum of the first $n$ terms of an arithmetic progression. If $S_{3n} = 3S_{2n}$,then the value of $\frac{S_{4n}}{S_{2n}}$ is:

  • A
    $4$
  • B
    $6$
  • C
    $8$
  • D
    $2$

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