Let $a, b, x, y$ be real numbers such that $a^2+b^2=81$,$x^2+y^2=121$ and $ax+by=99$. Then,the set of all possible values of $ay-bx$ is
- A$(0, \frac{9}{11}]$
- B$(0, \frac{9}{11})$
- C$\{0\}$
- D$[\frac{9}{11}, \infty)$
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