Let $A$ be a square matrix such that $AA^T = I$. Then $\frac{1}{2} A[(A+A^T)^2 + (A-A^T)^2]$ is equal to

  • A
    $A^2+I$
  • B
    $A^3+I$
  • C
    $A^2+A^T$
  • D
    $A^3+A^T$

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