Let $a=2 \hat{i}-3 \hat{j}+4 \hat{k}$, $b=7 \hat{i}+2 \hat{j}-3 \hat{k}$, and $c=\hat{i}+\hat{j}+\hat{k}$. The vector $x$ such that $x \cdot c=60$ and $x$ is perpendicular to both $a$ and $b$ is:

  • A
    $14 \hat{i}-6 \hat{j}-12 \hat{k}$
  • B
    $\hat{i}+34 \hat{j}+25 \hat{k}$
  • C
    $4 \hat{i}-21 \hat{j}-12 \hat{k}$
  • D
    $6 \hat{i}-6 \hat{j}+28 \hat{k}$

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