Let $f(x) = 1 - \sqrt{x^2}$, where the square root is to be taken as positive. Then:

  • A
    $f$ has no extrema at $x = 0$
  • B
    $f$ has minima at $x = 0$
  • C
    $f$ has maxima at $x = 0$
  • D
    $f'(0)$ exists

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