In Delta PQR,PQ = 7.5 , cm,QR = 6.2 , cm and | vedclass

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(A) According to the triangle inequality theorem,the sum of any two sides of a triangle is always greater than the third side,and the difference of an

Vedclass · Accepted Answer

$a = 1.3, b = 13.7$

Vedclass · Answer

(A) According to the triangle inequality theorem,the sum of any two sides of a triangle is always greater than the third side,and the difference of any two sides is always less than the third side.Given sides are $PQ = 7.5 \, cm$ and $QR = 6.2 \, cm$.Let the third side be $PR$.$1$. The difference of the two sides must be less than the third side: $PR > |PQ - QR| = |7.5 - 6.2| = 1.3 \, cm$.$2$. The sum of the two sides must be greater than the third side: $PR Therefore,$1.3 Comparing this with $a < PR < b$,we get $a = 1.3$ and $b = 13.7$.

In $\Delta PQR$,$PQ = 7.5 \, cm$,$QR = 6.2 \, cm$ and $a < PR < b$,then find the values of $a$ and $b$ in $cm$.

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