Match List-$I$ with List-$II$.
List-$I$List-$II$
$(A)$ Isothermal$(I)$ $\Delta W = 0$
$(B)$ Adiabatic$(II)$ $\Delta Q = 0$
$(C)$ Isobaric$(III)$ $\Delta U \neq 0$
$(D)$ Isochoric$(IV)$ $\Delta U = 0$

Choose the correct answer from the options given below:

  • A
    $(A)-(III), (B)-(II), (C)-(I), (D)-(IV)$
  • B
    $(A)-(IV), (B)-(I), (C)-(III), (D)-(II)$
  • C
    $(A)-(IV), (B)-(II), (C)-(III), (D)-(I)$
  • D
    $(A)-(II), (B)-(IV), (C)-(I), (D)-(III)$

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An ideal gas undergoes a thermodynamic cycle as shown in the figure. Which of the following graphs represents the same cycle?

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In the figure,a container is shown to have a movable (frictionless) piston on top. The container and the piston are made of perfectly insulating material,allowing no heat transfer between the outside and inside. The container is divided into two compartments by a rigid partition made of a thermally conducting material that allows slow heat transfer. The lower compartment is filled with $2$ moles of an ideal monatomic gas at $700 \ K$,and the upper compartment is filled with $2$ moles of an ideal diatomic gas at $400 \ K$. The heat capacities per mole are: for monatomic gas,$C_v = \frac{3}{2} R, C_p = \frac{5}{2} R$; for diatomic gas,$C_v = \frac{5}{2} R, C_p = \frac{7}{2} R$.
$1.$ Consider the partition to be rigidly fixed so that it does not move. When equilibrium is achieved,the final temperature of the gases will be:
$(A) 550 \ K$ $(B) 525 \ K$ $(C) 513 \ K$ $(D) 490 \ K$
$2.$ Now consider the partition to be free to move without friction so that the pressure of gases in both compartments is the same. Then the total work done by the gases until they achieve equilibrium will be:
$(A) 250 \ R$ $(B) 200 \ R$ $(C) 100 \ R$ $(D) -100 \ R$
Give the answer for questions $1$ and $2$.

An ideal gas undergoes a cyclic thermodynamic process in different ways as shown in the corresponding $P-V$ diagrams in column $3$ of the table. Consider only the path from state $1$ to $2$. $W$ denotes the corresponding work done on the system. The equations and plots in the table have standard notations as used in thermodynamic processes. Here $\gamma$ is the ratio of heat capacities at constant pressure and constant volume. The number of moles in the gas is $n$.
Column $I$Column $II$Column $III$
$(I)$ $W_{1-2} = \frac{1}{\gamma-1}(P_2V_2 - P_1V_1)$$(i)$ Isothermal$(P)$ [Graph $P$]
$(II)$ $W_{1-2} = -P(V_2 - V_1)$(ii) Isochoric$(Q)$ [Graph $Q$]
$(III)$ $W_{1-2} = 0$(iii) Isobaric$(R)$ [Graph $R$]
$(IV)$ $W_{1-2} = -nRT \ln(\frac{V_2}{V_1})$(iv) Adiabatic$(S)$ [Graph $S$]

$(1)$ Which of the following options is the only correct representation of a process in which $\Delta U = \Delta Q - P \Delta V$?
$[A] (II) (iii) (P)$ $[B] (II) (iii) (R)$ $[C] (II) (iv) (S)$ $[D] (III) (iii) (P)$
$(2)$ Which one of the following options is the correct combination?
$[A] (III) (ii) (S)$ $[B] (II) (iv) (R)$ $[C] (II) (iv) (P)$ $[D] (IV) (ii) (S)$
$(3)$ Which one of the following options correctly represents a thermodynamic process that is used as a correction in the determination of the speed of sound in an ideal gas?
$[A] (III) (iv) (R)$ $[B] (I) (ii) (Q)$ $[C] (I) (iv) (Q)$ $[D] (I) (iv) (R)$

One mole of a monoatomic gas and one mole of a diatomic gas are initially in the same state. Both gases are expanded isothermally and then adiabatically,such that they acquire the same final state. Choose the correct statement.

Match the following $:-$
Column-$I$ Column-$II$
$(i)$ Adiabatic process $(a)$ Constant temperature
$(ii)$ Isolated system $(b)$ No exchange of energy and matter
$(iii)$ Isothermal change $(c)$ First law of thermodynamics
$(iv)$ Law of conservation of energy $(d)$ No transfer of heat only

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