Match List-I with List-II: List-I Lis | vedclass

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(B) Isothermal process: In this process, the temperature of the system remains constant $(\Delta T = 0)$. Thus, $(a) \rightarrow (ii)$.$(b)$ Isochoric

Vedclass · Accepted Answer

$(a) \rightarrow (ii), (b) \rightarrow (iii), (c) \rightarrow (iv), (d) \rightarrow (i)$

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(B) Isothermal process: In this process, the temperature of the system remains constant $(\Delta T = 0)$. Thus, $(a) \rightarrow (ii)$.$(b)$ Isochoric process: In this process, the volume of the system remains constant $(\Delta V = 0)$. Thus, $(b) \rightarrow (iii)$.$(c)$ Adiabatic process: In this process, there is no exchange of heat between the system and the surroundings $(\Delta Q = 0)$. Thus, the heat content remains constant. So, $(c) \rightarrow (iv)$.$(d)$ Isobaric process: In this process, the pressure of the system remains constant $(\Delta P = 0)$. Thus, $(d) \rightarrow (i)$.Therefore, the correct matching is $(a) \rightarrow (ii), (b) \rightarrow (iii), (c) \rightarrow (iv), (d) \rightarrow (i)$.

List-$I$	List-$II$
$(a)$ Isothermal	$(i)$ Pressure constant
$(b)$ Isochoric	$(ii)$ Temperature constant
$(c)$ Adiabatic	$(iii)$ Volume constant
$(d)$ Isobaric	$(iv)$ Heat content is constant

Match List-$I$ with List-$II$:

List-$I$ List-$II$

$(a)$ Isothermal $(i)$ Pressure constant

$(b)$ Isochoric $(ii)$ Temperature constant

$(c)$ Adiabatic $(iii)$ Volume constant

$(d)$ Isobaric $(iv)$ Heat content is constant

Choose the correct answer from the options given below:

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Match List-$I$ with List-$II$: List-$I$ List-$II$ $(a)$ Isothermal $(i)$ Pressure constant $(b)$ Isochoric $(ii)$ Temperature constant $(c)$ Adiabatic $(iii)$ Volume constant $(d)$ Isobaric $(iv)$ Heat content is constant Choose the correct answer from the options given below: