Negation of p wedge (sim q vee sim r) is - | vedclass

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(B) We need to find the negation of $p \wedge (\sim q \vee \sim r)$.Using De Morgan's Law,$\sim (A \wedge B) = \sim A \vee \sim B$.$\sim (p \wedge (\s

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$(\sim p \vee q) \wedge (\sim p \vee r)$

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(B) We need to find the negation of $p \wedge (\sim q \vee \sim r)$.Using De Morgan's Law,$\sim (A \wedge B) = \sim A \vee \sim B$.$\sim (p \wedge (\sim q \vee \sim r)) = \sim p \vee \sim (\sim q \vee \sim r)$.Applying De Morgan's Law again,$\sim (\sim q \vee \sim r) = (\sim \sim q \wedge \sim \sim r) = (q \wedge r)$.So,the expression becomes $\sim p \vee (q \wedge r)$.Using the distributive law,$A \vee (B \wedge C) = (A \vee B) \wedge (A \vee C)$.Therefore,$\sim p \vee (q \wedge r) = (\sim p \vee q) \wedge (\sim p \vee r)$.

Negation of $p \wedge (\sim q \vee \sim r)$ is -

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