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(A) Young's modulus $Y$ is defined as the ratio of longitudinal stress to longitudinal strain:$Y = \frac{F/A}{\Delta l/l} = \frac{Fl}{A \Delta l}$Rear

Vedclass · Accepted Answer

$0.025$

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(A) Young's modulus $Y$ is defined as the ratio of longitudinal stress to longitudinal strain:$Y = \frac{F/A}{\Delta l/l} = \frac{Fl}{A \Delta l}$Rearranging for the change in length $\Delta l$:$\Delta l = \frac{Fl}{AY}$Given:Force $F = mg = 1000 \,kg 	imes 10 \,ms^{-2} = 10,000 \,N$Length $l = 50 \,cm = 0.5 \,m$Area $A = 1000 \,mm^2 = 1000 	imes 10^{-6} \,m^2 = 10^{-3} \,m^2$Young's modulus $Y = 2 	imes 10^{11} \,Nm^{-2}$Substituting the values:$\Delta l = \frac{10,000 	imes 0.5}{10^{-3} 	imes 2 	imes 10^{11}}$$\Delta l = \frac{5,000}{2 	imes 10^8} = 2,500 	imes 10^{-8} \,m = 2.5 	imes 10^{-5} \,m$Converting to millimeters:$\Delta l = 2.5 	imes 10^{-5} 	imes 10^3 \,mm = 0.025 \,mm$

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