(A) Let the equation of the circle be $S(x, y) = x^2 + y^2 - x + y - 1 = 0$. To find the position of the point $(1, 1)$,we substitute $x = 1$ and $y =

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(A) Let the equation of the circle be $S(x, y) = x^2 + y^2 - x + y - 1 = 0$. To find the position of the point $(1, 1)$,we substitute $x = 1$ and $y = 1$ into the expression $S(x, y)$. $S(1, 1) = (1)^2 + (1)^2 - (1) + (1) - 1 = 1 + 1 - 1 + 1 - 1 = 1$. Since $S(1, 1) = 1 > 0$,the point $(1, 1)$ lies outside the circle.

Class 11 Mathematics 10-1.Circle and System of Circles Geometrical problems regarding circle and its properties

Easy

Position of the point $(1, 1)$ with respect to the circle $x^2 + y^2 - x + y - 1 = 0$ is

A
Outside the circle
B
Upon the circle
C
Inside the circle
D
None of these

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10-1.Circle and System of Circles

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Geometrical problems regarding circle and its properties

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Position of the point $(1, 1)$ with respect to the circle $x^2 + y^2 - x + y - 1 = 0$ is

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