Predict the major product of the following re | vedclass

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(C) The reaction proceeds in two main steps: $1$. Claisen-Schmidt condensation: Acetophenone reacts with $4$-methylbenzaldehyde in the presence of $Na

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(C) The reaction proceeds in two main steps: $1$. Claisen-Schmidt condensation: Acetophenone reacts with $4$-methylbenzaldehyde in the presence of $NaOH$ to form an $\alpha,\beta$-unsaturated ketone (chalcone derivative). $2$. Michael addition: The lithium enolate of cyclohexanone performs a conjugate addition (Michael addition) to the $\alpha,\beta$-unsaturated ketone formed in the first step. Following the mechanism,the enolate attacks the $\beta$-carbon of the unsaturated system. After protonation with $H_2O$,the final product is the one where the cyclohexanone ring is attached to the $\beta$-carbon of the original chalcone structure. Comparing this with the given options,the structure matches option $C$.

Predict the major product of the following reaction sequence:

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The major product formed in the following reaction is:

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