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(B) The reaction sequence is as follows:$1$. Phthalic anhydride reacts with $LiAlH_4$ (a strong reducing agent) to reduce both carbonyl groups of the

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Phthalazine

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(B) The reaction sequence is as follows:$1$. Phthalic anhydride reacts with $LiAlH_4$ (a strong reducing agent) to reduce both carbonyl groups of the anhydride to primary alcohol groups,forming benzene$-1,2-$dimethanol (compound $A$).$2$. Compound $A$ (benzene$-1,2-$dimethanol) is then treated with $PCC$ (Pyridinium chlorochromate),which is a mild oxidizing agent that selectively oxidizes primary alcohols to aldehydes. This converts both $-CH_2OH$ groups into $-CHO$ groups,forming phthalaldehyde (compound $B$).$3$. Finally,phthalaldehyde reacts with hydrazine $(NH_2-NH_2)$ via a condensation reaction (forming a cyclic hydrazone),which results in the formation of phthalazine (compound $C$).

Product $(C)$ is

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