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(B) The reaction is a Beckmann rearrangement of benzophenone oxime in the presence of $H_2SO_4$ and $H_2^{18}O$.In the Beckmann rearrangement,the oxim

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$Ph-NH-C(^{18}O)-Ph$

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(B) The reaction is a Beckmann rearrangement of benzophenone oxime in the presence of $H_2SO_4$ and $H_2^{18}O$.In the Beckmann rearrangement,the oxime undergoes protonation followed by the migration of a phenyl group to the nitrogen atom,resulting in the formation of a nitrilium ion.This nitrilium ion is then attacked by the labeled water molecule $(H_2^{18}O)$.After the loss of a proton,an imidic acid intermediate is formed,which tautomerizes to the final amide product,$N$-phenylbenzamide,containing the $^{18}O$ isotope in the carbonyl group: $Ph-NH-C(^{18}O)-Ph$.

The product $(A)$ of the reaction is:

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