The product of the given reaction is:

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Question

(A) The reaction is an $S_NAr$ (nucleophilic aromatic substitution) reaction. The $-NO_2$ group is a strong electron-withdrawing group that activates

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$4-$bromo$-2-$nitrophenol

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(A) The reaction is an $S_NAr$ (nucleophilic aromatic substitution) reaction. The $-NO_2$ group is a strong electron-withdrawing group that activates the ortho and para positions towards nucleophilic attack. In $1-bromo-4-bromo-2-nitrobenzene$ (or $1,4-dibromo-2-nitrobenzene$),the bromine atom at the para position relative to the $-NO_2$ group is more susceptible to nucleophilic substitution by $HO^-$ due to the resonance stabilization of the Meisenheimer complex intermediate. Therefore,the $HO^-$ group replaces the para-bromine atom to form $4-bromo-2-nitrophenol$.

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