Rachana had an average score of $45$ from $6$ tests. Her teacher dropped her lowest score,which is $30$,and calculated the average of the remaining scores to decide her grade. Which of the following gives her new average score?

  • A
    $\frac{(45 \times 5 - 30)}{5}$
  • B
    $\frac{(45 \times 5 - 30)}{6}$
  • C
    $\frac{(45 \times 6 - 30)}{5}$
  • D
    $\frac{(45 \times 6 - 30)}{6}$

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Similar Questions

The formula to find the mean of an ungrouped data is ........

While computing the mean of grouped data,we assume that the frequencies are

The mean of the following data is $26.5$ and the total frequency is $60$. Find the missing frequencies $x$ and $y$.
Class$0-10$$10-20$$20-30$$30-40$$40-50$
Frequency$6$$x$$17$$y$$8$

Calculate the mean of the following data:
Class $4-7$ $8-11$ $12-15$ $16-19$
Frequency $5$ $4$ $9$ $10$

The median class of the following frequency distribution is ...........
Class$0-10$$10-20$$20-30$$30-40$$40-50$$50-60$
Frequency$4$$5$$9$$10$$14$$8$

Total frequency $n = 50$.

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