Medium
The reaction rate between two substances $A$ and $B$ is expressed as: $\text{rate} = k[A]^n[B]^m$. If the concentration of $A$ is doubled and the concentration of $B$ is halved,the ratio of the new rate to the initial rate will be:
- A$2^{(m+n)}$
- B$n-m$
- C$\frac{1}{2^{(m+n)}}$
- D$2^{(n-m)}$
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