Represent the following data by means of a histogram:

Class	$0-5$	$5-10$	$10-20$	$20-30$	$30-50$	$50-70$
Frequency	$5$	$7$	$12$	$16$	$24$	$16$

Here,the class intervals have unequal widths. Therefore,we must first compute the adjusted frequencies for each class. The minimum class size is $5 - 0 = 5$. The adjusted frequencies are calculated using the following formula:
$\text{Adjusted frequency of a class} = \frac{\text{Frequency of the class}}{\text{Class size}} \times \text{Minimum class size}$
The adjusted frequencies are calculated in the table below:

Class	Frequency	Class size	Adjusted frequency (Height of rectangle)
$0-5$	$5$	$5$	$(5/5) \times 5 = 5$
$5-10$	$7$	$5$	$(7/5) \times 5 = 7$
$10-20$	$12$	$10$	$(12/10) \times 5 = 6$
$20-30$	$16$	$10$	$(16/10) \times 5 = 8$
$30-50$	$24$	$20$	$(24/20) \times 5 = 6$
$50-70$	$16$	$20$	$(16/20) \times 5 = 4$

Using these adjusted frequencies,we plot the histogram where the $x$-axis represents the class intervals and the $y$-axis represents the adjusted frequencies (heights of the rectangles).