Represent the following situation in the form of a quadratic equation:
The product of two consecutive positive integers is $306$. We need to find the integers.
The product of two consecutive positive integers is $306$. We need to find the integers.
(N/A) Let the two consecutive positive integers be $x$ and $x+1$.
According to the problem,the product of these two integers is $306$.
Therefore,$x(x+1) = 306$.
Expanding the equation,we get $x^2 + x = 306$.
Subtracting $306$ from both sides,we obtain the quadratic equation: $x^2 + x - 306 = 0$.
According to the problem,the product of these two integers is $306$.
Therefore,$x(x+1) = 306$.
Expanding the equation,we get $x^2 + x = 306$.
Subtracting $306$ from both sides,we obtain the quadratic equation: $x^2 + x - 306 = 0$.
Explore More
Similar Questions
Check whether the following is a quadratic equation:
$x^{2}+3x+1=(x-2)^{2}$
$x^{2}+3x+1=(x-2)^{2}$
Easy
View SolutionSum of the areas of two squares is $468 \, m^2$. If the difference of their perimeters is $24 \, m$,find the sides of the two squares.
Medium
View SolutionFind the roots of the quadratic equation $6x^{2}-x-2=0$.
Medium
View SolutionFind the roots of the following quadratic equation by factorisation:
$2x^{2} - x + \frac{1}{8} = 0$
$2x^{2} - x + \frac{1}{8} = 0$
Easy
View SolutionFind the roots of the following equation:
$x + \frac{1}{x} = 3, x \neq 0$
$x + \frac{1}{x} = 3, x \neq 0$
Medium
View SolutionVedclass Products
For Students
Vedclass Test Series
Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.
Start Free TrialFor Teachers
Exam Paper Generator
Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.
Try FreeFor Institutes
Online Exam Module
Live online exams with unlimited students, 360° analytics & white-label branding.
See Demo