Solve $3x - 6 \geq 0$ graphically in a two-dimensional plane.

(N/A) First,consider the corresponding equation $3x - 6 = 0$,which simplifies to $x = 2$.
Draw the line $x = 2$ in the Cartesian plane. Since the inequality is $\geq$,the line $x = 2$ is included in the solution region (represented by a solid line).
To determine the solution region,test a point not on the line,such as $(0, 0)$.
Substituting $(0, 0)$ into the inequality $3x - 6 \geq 0$ gives $3(0) - 6 \geq 0$,which simplifies to $-6 \geq 0$.
Since $-6 \geq 0$ is false,the origin $(0, 0)$ does not lie in the solution region.
Therefore,the solution region is the half-plane to the right of the line $x = 2$,including the line itself.