Solve the following pair of linear equations | vedclass

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(B) Given equations are:$5x + 2y - 10 = 0$  ---$(1)$$4x + 3y - 1 = 0$   ---$(2)$Comparing with $a_1x + b_1y + c_1 = 0$ and $a_2x + b_2y + c_2 = 0$:$a_

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$(4, -5)$

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(B) Given equations are:$5x + 2y - 10 = 0$  ---$(1)$$4x + 3y - 1 = 0$   ---$(2)$Comparing with $a_1x + b_1y + c_1 = 0$ and $a_2x + b_2y + c_2 = 0$:$a_1 = 5, b_1 = 2, c_1 = -10$$a_2 = 4, b_2 = 3, c_2 = -1$Using the cross-multiplication formula:$\frac{x}{b_1c_2 - b_2c_1} = \frac{y}{c_1a_2 - c_2a_1} = \frac{1}{a_1b_2 - a_2b_1}$$\frac{x}{(2)(-1) - (3)(-10)} = \frac{y}{(-10)(4) - (-1)(5)} = \frac{1}{(5)(3) - (4)(2)}$$\frac{x}{-2 + 30} = \frac{y}{-40 + 5} = \frac{1}{15 - 8}$$\frac{x}{28} = \frac{y}{-35} = \frac{1}{7}$For $x$: $\frac{x}{28} = \frac{1}{7} \implies x = \frac{28}{7} = 4$For $y$: $\frac{y}{-35} = \frac{1}{7} \implies y = \frac{-35}{7} = -5$Thus,the solution is $(4, -5)$.

Solve the following pair of linear equations using the cross-multiplication method:
$5x + 2y = 10$
$4x + 3y - 1 = 0$

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Solve the following pair of linear equations using the cross-multiplication method:$5x + 2y = 10$$4x + 3y - 1 = 0$