Solve the following system of inequalities:
$8x + 3y \leq 100$ $(1)$
$x \geq 0$ $(2)$
$y \geq 0$ $(3)$

(N/A) First,we draw the graph of the line $8x + 3y = 100$.
To find the intercepts,if $x = 0$,then $3y = 100 \implies y = 33.33$. If $y = 0$,then $8x = 100 \implies x = 12.5$.
The inequality $8x + 3y \leq 100$ represents the shaded region below the line,including the points on the line $8x + 3y = 100$.
Since $x \geq 0$ and $y \geq 0$,the solution is restricted to the first quadrant.
Thus,every point in the shaded region in the first quadrant,including the points on the line and the axes,represents the solution of the given system of inequalities.