Solve the given inequality for real x: frac{3 | vedclass

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(A) Given inequality: $\frac{3(x-2)}{5} \leq \frac{5(2-x)}{3}$Multiply both sides by $15$ (the $LCM$ of $3$ and $5$):$9(x-2) \leq 25(2-x)$Expand the t

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$(-\infty, 2]$

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(A) Given inequality: $\frac{3(x-2)}{5} \leq \frac{5(2-x)}{3}$Multiply both sides by $15$ (the $LCM$ of $3$ and $5$):$9(x-2) \leq 25(2-x)$Expand the terms:$9x - 18 \leq 50 - 25x$Add $25x$ to both sides:$9x + 25x - 18 \leq 50$$34x - 18 \leq 50$Add $18$ to both sides:$34x \leq 50 + 18$$34x \leq 68$Divide by $34$:$x \leq 2$Thus,the solution set is $(-\infty, 2]$.

Solve the given inequality for real $x$: $\frac{3(x-2)}{5} \leq \frac{5(2-x)}{3}$

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