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(D) For equation $I: x^{2} + 12x + 32 = 0$Factorizing the quadratic equation: $x^{2} + 8x + 4x + 32 = 0$$x(x + 8) + 4(x + 8) = 0$$(x + 4)(x + 8) = 0$T

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if $x = y$ or relationship between $x$ and $y$ cannot be established.

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(D) For equation $I: x^{2} + 12x + 32 = 0$Factorizing the quadratic equation: $x^{2} + 8x + 4x + 32 = 0$$x(x + 8) + 4(x + 8) = 0$$(x + 4)(x + 8) = 0$Thus,$x = -4$ or $x = -8$.For equation $II: 2y^{2} + 15y + 27 = 0$Factorizing the quadratic equation: $2y^{2} + 6y + 9y + 27 = 0$$2y(y + 3) + 9(y + 3) = 0$$(2y + 9)(y + 3) = 0$Thus,$y = -4.5$ or $y = -3$.Comparing the values:When $x = -4$,$x > y$ (since $-4 > -4.5$) and $x When $x = -8$,$x Since the relationship changes depending on the values chosen,the relationship between $x$ and $y$ cannot be established.

Solve the given two equations and select the correct answer from the given options.
$I. x^{2} + 12x + 32 = 0$
$II. 2y^{2} + 15y + 27 = 0$

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Solve the given two equations and select the correct answer from the given options.$I. x^{2} + 12x + 32 = 0$$II. 2y^{2} + 15y + 27 = 0$