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(A) For equation $I: 6x^{2} - 49x + 99 = 0$We need two numbers whose product is $6 	imes 99 = 594$ and sum is $49$.The numbers are $22$ and $27$.$6x^

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if $x > y$

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(A) For equation $I: 6x^{2} - 49x + 99 = 0$We need two numbers whose product is $6 	imes 99 = 594$ and sum is $49$.The numbers are $22$ and $27$.$6x^{2} - 22x - 27x + 99 = 0$$2x(3x - 11) - 9(3x - 11) = 0$$(2x - 9)(3x - 11) = 0$$x = \frac{9}{2} = 4.5$ or $x = \frac{11}{3} \approx 3.67$For equation $II: 5y^{2} + 17y + 14 = 0$We need two numbers whose product is $5 	imes 14 = 70$ and sum is $17$.The numbers are $10$ and $7$.$5y^{2} + 10y + 7y + 14 = 0$$5y(y + 2) + 7(y + 2) = 0$$(5y + 7)(y + 2) = 0$$y = -\frac{7}{5} = -1.4$ or $y = -2$Comparing the values:$x$ values are $4.5$ and $3.67$.$y$ values are $-1.4$ and $-2$.Since all values of $x$ are greater than all values of $y$,we have $x > y$.

Solve the given two equations and select the correct answer from the given options.
$I. \quad 6x^{2} - 49x + 99 = 0$
$II. \quad 5y^{2} + 17y + 14 = 0$

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Solve the given two equations and select the correct answer from the given options.$I. \quad 6x^{2} - 49x + 99 = 0$$II. \quad 5y^{2} + 17y + 14 = 0$