Solve the inequality for real x: frac{3-2x}{5 | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) Given the inequality: $\frac{3-2x}{5} < \frac{x}{3} + 2$ Multiply the entire inequality by $15$ (the least common multiple of $5$ and $3$) to clea

Vedclass · Accepted Answer

$x \in (-\frac{21}{11}, \infty)$

Vedclass · Answer

(A) Given the inequality: $\frac{3-2x}{5} Multiply the entire inequality by $15$ (the least common multiple of $5$ and $3$) to clear the denominators: $15 	imes \frac{3-2x}{5} $3(3-2x) $9 - 6x Subtract $5x$ from both sides: $9 - 11x Subtract $9$ from both sides: $-11x Divide by $-11$ and reverse the inequality sign: $x > -\frac{21}{11}$ Thus,the solution set is $x \in (-\frac{21}{11}, \infty)$.

Solve the inequality for real $x$: $\frac{3-2x}{5} < \frac{x}{3} + 2$

Similar Questions

Solve the inequality for real $x$: $3(2x - 1) + 5 \leq \frac{1}{2}(x + 15)$

Solve the system of inequalities:
$3x - 7 < 5 + x$ ..... $(1)$
$11 - 5x \leqslant 1$ ..... $(2)$
and represent the solutions on the number line.

The solution set of $|x-1|+|x+1| < 2$ is

Solve the following inequality and represent it on a number line: $\frac{4x+1}{9} > \frac{9x+1}{4} - 2$

Solve for $x$ the inequality: $\frac{|x-2|-1}{|x-2|-2} \leq 0$

Vedclass Test Series

Exam Paper Generator

Online Exam Module