The [Co(H_2O)_6]^{2+} ion has three unpaired | vedclass

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(C) The atomic number of $Co$ is $27$. The electronic configuration of $Co^{2+}$ is $[Ar] 3d^7$.Since $H_2O$ is a weak field ligand,it does not cause

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$sp^3d^2$

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(C) The atomic number of $Co$ is $27$. The electronic configuration of $Co^{2+}$ is $[Ar] 3d^7$.Since $H_2O$ is a weak field ligand,it does not cause pairing of electrons in the $3d$ orbitals.Thus,the $3d$ orbitals have $3$ unpaired electrons.The hybridization involves the use of one $4s$,three $4p$,and two $4d$ orbitals to accommodate the six ligands.Therefore,the hybridization is $sp^3d^2$.

The $[Co(H_2O)_6]^{2+}$ ion has three unpaired electrons. The hybridization of $Co$ in $[Co(H_2O)_6]^{2+}$ is

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