The adjacent sides of a parallelogram are 8, | vedclass

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(B) The area of a parallelogram is given by the product of a base and its corresponding height (distance between parallel sides).Let the sides be $a =

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$6.4$

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(B) The area of a parallelogram is given by the product of a base and its corresponding height (distance between parallel sides).Let the sides be $a = 8\, m$ and $b = 5\, m$.The distance between the longer sides $(8\, m)$ is given as $h_1 = 4\, m$.Therefore,the area of the parallelogram $= 	ext{base} 	imes 	ext{height} = 8\, m 	imes 4\, m = 32\, m^2$.Let the distance between the shorter sides $(5\, m)$ be $h_2$.Since the area remains the same,we have $5\, m 	imes h_2 = 32\, m^2$.$h_2 = \frac{32}{5} = 6.4\, m$.Thus,the distance between the shorter sides is $6.4\, m$.

The adjacent sides of a parallelogram are $8\, m$ and $5\, m$. The distance between the longer sides is $4\, m$. The distance between the shorter sides is......$m$.

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