An ammeter has a range of 1 , A without a shu | vedclass

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(B) Let $I_g$ be the full-scale deflection current of the galvanometer and $G$ be its resistance. The initial range is $I_0 = I_g = 1 \, A$.When a shu

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$Q$

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(B) Let $I_g$ be the full-scale deflection current of the galvanometer and $G$ be its resistance. The initial range is $I_0 = I_g = 1 \, A$.When a shunt resistance $S$ is connected in parallel,the new range $I$ is given by the formula: $I = I_g \left(1 + \frac{G}{S}ight)$.Since $I_g = 1 \, A$,we have $I = 1 + \frac{G}{S}$.Rearranging for $S$,we get: $S = \frac{G}{I - 1}$.This equation represents a rectangular hyperbola where $S 	o \infty$ as $I 	o 1$ and $S 	o 0$ as $I 	o \infty$. Looking at the graph,the curve $Q$ represents this hyperbolic relationship starting from the range $1 \, A$ on the $x$-axis.

An ammeter has a range of $1 \, A$ without a shunt. The range can be varied by using different shunt resistances. The graph between shunt resistance $(S)$ and range $(I)$ will have the nature of which curve shown in the figure?

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