(A) The maximum acceleration $a_{max}$ of a particle executing $S.H.M.$ is given by the formula $a_{max} = A\omega^2$.Here,$A = 0.01 \, m$ is the ampl

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(A) The maximum acceleration $a_{max}$ of a particle executing $S.H.M.$ is given by the formula $a_{max} = A\omega^2$.Here,$A = 0.01 \, m$ is the amplitude and $n = 60 \, Hz$ is the frequency.Since $\omega = 2\pi n$,we have $\omega^2 = 4\pi^2 n^2$.Substituting the values: $a_{max} = 0.01 \times 4\pi^2 \times (60)^2$.$a_{max} = 0.01 \times 4\pi^2 \times 3600$.$a_{max} = 144\pi^2 \, m/s^2$.

Class 11 Physics Oscillations Acceleration and Force of Simple Harmonic Motion

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The amplitude of a particle executing $S.H.M.$ with a frequency of $60 \, Hz$ is $0.01 \, m$. The maximum value of the acceleration of the particle is

A
$144\pi^2 \, m/s^2$
B
$144 \, m/s^2$
C
$\frac{144}{\pi^2} \, m/s^2$
D
$288\pi^2 \, m/s^2$

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Oscillations

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Acceleration and Force of Simple Harmonic Motion

Which of the following quantities is always negative in a $SHM$?

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$A$ particle is performing $S.H.M.$ starting from the extreme position. The graphical representation shows that between displacement and acceleration,there is a phase difference of:

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Values of the acceleration $A$ of a particle moving in simple harmonic motion as a function of its displacement $x$ are given in the table below:
$A \ (mm \ s^{-2})$ $16$ $8$ $0$ $-8$ $-16$
$x \ (mm)$ $-4$ $-2$ $0$ $2$ $4$

The period of the motion is:

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The displacement of a particle varies with time as $x = 12 \sin \omega t - 16 \sin^3 \omega t$ (in $cm$). If its motion is $S.H.M.$,then its maximum acceleration is

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Write the force law for $SHM$.

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$A \ (mm \ s^{-2})$	$16$	$8$	$0$	$-8$	$-16$
$x \ (mm)$	$-4$	$-2$	$0$	$2$	$4$

The amplitude of a particle executing $S.H.M.$ with a frequency of $60 \, Hz$ is $0.01 \, m$. The maximum value of the acceleration of the particle is

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Which of the following quantities is always negative in a $SHM$?

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Values of the acceleration $A$ of a particle moving in simple harmonic motion as a function of its displacement $x$ are given in the table below:
$A \ (mm \ s^{-2})$ $16$ $8$ $0$ $-8$ $-16$
$x \ (mm)$ $-4$ $-2$ $0$ $2$ $4$

The period of the motion is: