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(D) For a particle in simple harmonic motion, the acceleration $A$ is given by $A = -\omega^2 x$, where $\omega$ is the angular frequency.Taking the m

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$\pi \ s$

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(D) For a particle in simple harmonic motion, the acceleration $A$ is given by $A = -\omega^2 x$, where $\omega$ is the angular frequency.Taking the magnitude, we have $|A| = \omega^2 |x|$, which implies $\omega^2 = \frac{|A|}{|x|}$.Using the values from the table (e.g., $|A| = 16 \ mm \ s^{-2}$ and $|x| = 4 \ mm$):$\omega^2 = \frac{16 \ mm \ s^{-2}}{4 \ mm} = 4 \ s^{-2}$.Therefore, $\omega = \sqrt{4} = 2 \ rad \ s^{-1}$.The time period $T$ is related to the angular frequency by the formula $T = \frac{2\pi}{\omega}$.Substituting the value of $\omega$:$T = \frac{2\pi}{2} = \pi \ s$.

$A \ (mm \ s^{-2})$	$16$	$8$	$0$	$-8$	$-16$
$x \ (mm)$	$-4$	$-2$	$0$	$2$	$4$

Values of the acceleration $A$ of a particle moving in simple harmonic motion as a function of its displacement $x$ are given in the table below:
$A \ (mm \ s^{-2})$ $16$ $8$ $0$ $-8$ $-16$
$x \ (mm)$ $-4$ $-2$ $0$ $2$ $4$

The period of the motion is:

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Values of the acceleration $A$ of a particle moving in simple harmonic motion as a function of its displacement $x$ are given in the table below:$A \ (mm \ s^{-2})$$16$$8$$0$$-8$$-16$$x \ (mm)$$-4$$-2$$0$$2$$4$The period of the motion is: